A 75 watt bulb draws 680 mA how much time will be required to pass 30 columb change through the bulb
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Explanation:
P = 75W
I = 680 mA = 680/1000 A
q = 30 coulombs
P = VI
=> V = 75 x 1000 / 680
=> V = 110V ( rounded off)
W = qV
= 30 x 110
= 3300J
T = W/P
= 3300 / 75
= 44 seconds ( approx)
Or you can directly do it this way :-
t = q/I
= 30 x 1000 / 680
= 44 seconds ( approx)
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