Question

A
75°
1. In figure1.55, 2 ABC=75°,
EDC=75° state which two triangles
are similar and by which test? Also
write the similarity of these two
triangles by a proper one to one
correspondence.
C
75°
E
B.
Fig. 1.55
Р​

Answer 1

Answer:

Δ ABC  ≅  Δ EDC

AC/EC  = BC/DC= AB/ED

Step-by-step explanation

in Δ ABC

∠ABC = 75 °

∠BCA = x °

∠BAC = 180° - 75° - x° = 105 - x°

in Δ EDC

∠EDC = 75 °

∠ECD = x °

∠CED = 180° - 75° - x° = 105 - x°

∠ABC = ∠EDC

∠BCA = ∠ECD

∠BAC = ∠CED

All the angles are same so

Δ ABC  ≅  Δ EDC

AC/EC  = BC/DC= AB/ED