A 75Kg block is placed on an inclined plane with an angle of 30o. Find the components of the weight of the block parallel and perpendicular to the incline plane
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The weight components are
In parallel,
W= mgsinβ= 75*10*sin30=375 N
In perpendicular,
W= mgcosβ= 75*10*cos30=649.51N
Cheers.
In parallel,
W= mgsinβ= 75*10*sin30=375 N
In perpendicular,
W= mgcosβ= 75*10*cos30=649.51N
Cheers.
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