Physics, asked by robertdaka6, 1 year ago

A 75Kg block is placed on an inclined plane with an angle of 30o. Find the components of the weight of the block parallel and perpendicular to the incline plane

Answers

Answered by khatriaashish24

1

The weight components are
In parallel,
W= mgsinβ= 75*10*sin30=375 N

In perpendicular,
W= mgcosβ= 75*10*cos30=649.51N
Cheers.

Previous Question

Next Question

Similar questions

English, 7 months ago

2, where 4 is of the form 245*, to an equivalent rational number of the form 9 where b is a power of 10. Therefore, the decimal expansion of such a rational mu terminates. Let us write down our result formally. Theorem 1.7. Letxe be a rational number, such that the prime factoria of 4 is the form 2254, where n, m are non-negative integers. Then the decimal expansion which terminates,...

Math, 7 months ago

If a table's length is .9 metere and width is .4 metere. Find the area of the table in square foot.

Art, 7 months ago

9. Stimuli from the environment are registered in our O sensory memory o short-term memory O long-term memory...

Science, 1 year ago

name of common species of cockroach...

Computer Science, 1 year ago

In a certain code '8 2 9' mean 'how art thou' ,'9 5 8' means 'thou art good' and '1 5 8 7 3' means 'thy good and thou bad' what may be the possible code for 'thy'...

Geography, 1 year ago

describe how relief features influence the climate of India...

Chemistry, 1 year ago

In a tug of war team he wins and team we lost . Which of these terms does a positive work...

Business Studies, 1 year ago

How has india and china helped Nepal...