Question

a 75kg mau stand in a lift . what force does the floor exert on him when the elevator starts moving upwards with an acceleration of 2.0ms‐²​

Answer 1

Answer:

hey mate here is the answer

Explanation:

N= ma + mg

= 75×2+75×10

= 900N

= 900/g kgf

= 90 kgf is correct answer

Answer 2

Answer:

hey mate here is the answer

Explanation:

N = ma+mg

= 75×2+75×10

= 900 N

= 900/g kgf

= 90 kgf

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Thank you.