Question

a. 7a²bc.-3 abc², 3a²bc 2abc²

add the following ​

Answer 1

Given terms are 7a

2

bc , −3abc

2

, 3a

2

bc , 2abc

2

Required sum =7a

2

bc+(−3abc

2

)+(3a

2

bc)+(2abc

2

)

Rearranging and collecting like terms,

=7a

2

bc+3a

2

bc−3abc

2

+2abc

2

=(7+3)a

2

bc+(−3+2)abc

2

=10a

2

bc−abc

2

Answer 2

From the given question the correct answer is:

the addition of 7a²bc.-3 abc², 3a²bc -2abc² is 5(2a²bc-abc²)

Given:

7a²bc.-3 abc², 3a²bc -2abc²

To find :

Addition 7a²bc.-3 abc², 3a²bc -2abc²

Solution:

we have to add the given expressions

so,

   7a²bc.-3abc²

  +3a²bc -2abc²

    10a²bc-5abc²

now , we take out 5 as the common

so we get,

5(2a²bc-abc²)

Hence, the addition of 7a²bc.-3 abc², 3a²bc -2abc² is 5(2a²bc-abc²)