Question

a 7cm high object is placed perpendicular to principal axis of a concave mirror the distance of the objectfrom the mirror is 40 cm and its image is formed at 40 cm from the mirror on the same side of the mirror as the object find focal length magnification height of image and ray diagram plzzzzzzz​

Answer 1

Answer:

Explanation:Height of the object =2 cm

U(object distance) = -15 as u is always negative

F = -10 (as it is always negative for concave miror and lens )

1/F =1/v + 1/u

-1/10 = 1/v + (-1/15)

-1/10 +1/15 =v

-3+2/30 =v

V=-30cm

Hi/Ho = - V/U

Hi /2 = -(-30/15)

Hi =-30×2÷15

Hi =-4cm (Real and inverted)

Answer 2

HEY MATE HERE IS YOUR ANSWER

HOPE IT HELPS YOU MARK IT AS BRAINLIEST