Physics, asked by AQUIB9803, 7 months ago

A 7Li nucleus with a charge of +3e and a mass of 7 u (1 u = 1.66 X 10-27 kg) and a proton with charge +e and mass 1 u are both moving in a plane perpendicular to a magnetic field B. The magnitude of the momenta of the two particles are equal. The ratio of the radius of curvature of the path of the proton, Rp' to that of the 7Li nucleus, RLi, is (a) Rpi RLi = 3. (b) Rp/RLi = 1/3. (c) Rp/Ru = 1/7. (d) Rp/RLi = 3/7. (e) none of these.

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Answered by saiyedtufaul
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