Math, asked by ankurkumar90, 3 days ago

A 7m wide path is to be constructed all around, and outside of a circular field of diameter 112 m. Find the cost of constructing the path at 750.​

Answers

Answered by siddarthkumar1233
0

105+7=112

22/7(112+105)

112-105=217

22/7×217×7

Answer = 4774

Answered by AmazingAkhil2006
2

Answer:

₹19,63,500

Step-by-step explanation:

Given-

  • The width of the path = 7m
  • Diameter of the circular field = 112m => Radius = 112/2 = 56m
  • Cost of constructing the path = ₹750 per m²

Solution-

The radius of the inner circle = 56  (r₁)

The radius of the outer circle = 56 + 7 => 63m (r₂)

The area of the track =>

πr₂²-πr₁²

=> π(r₂²- r₁²)

=> 22/7 × ( 63²- 56²)

=> 22/7 × ((63+56) (63-56))    (a²-b² = (a+b) (a-b))

=> 22/7 × 119 × 7

=> 22 × 119   (7 and 7 is cancelled)

=> 2618 m²

Now,

The cost of constructing 2618m² of path = 2618 × 750

=> ₹ 19,63,500

I hope it helped you!!!

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