A 7m wide path is to be constructed all around, and outside of a circular field of diameter 112 m. Find the cost of constructing the path at 750.
Answers
Answered by
0
105+7=112
22/7(112+105)
112-105=217
22/7×217×7
Answer = 4774
Answered by
2
Answer:
₹19,63,500
Step-by-step explanation:
Given-
- The width of the path = 7m
- Diameter of the circular field = 112m => Radius = 112/2 = 56m
- Cost of constructing the path = ₹750 per m²
Solution-
The radius of the inner circle = 56 (r₁)
The radius of the outer circle = 56 + 7 => 63m (r₂)
The area of the track =>
πr₂²-πr₁²
=> π(r₂²- r₁²)
=> 22/7 × ( 63²- 56²)
=> 22/7 × ((63+56) (63-56)) (a²-b² = (a+b) (a-b))
=> 22/7 × 119 × 7
=> 22 × 119 (7 and 7 is cancelled)
=> 2618 m²
Now,
The cost of constructing 2618m² of path = 2618 × 750
=> ₹ 19,63,500
I hope it helped you!!!
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