Question

A 7m wild road run around a circular Park whose circumference is 176 m find the cost of fencing the outer boundary of the road at the rate of rupees 21 per metre













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Answer 1

Step-by-step explanation:

Circumference = 2πr = 176

π = 22/7

2πr = 44r/7 = 176

r = 7×176/44

r = 28m

since, the road is 7m wide and a fence is to be put on the outer boundary, the new radius becomes 7+28, which is 35m

therefore, circumference = 2×π×35

= 2×22×35/7

=2×22×5

=220m

the rate of fencing is Rs. 21 per m

thus the cost of fencing = 21×220 = Rs. 4620

Answer 2

Answer:

220m is the answer mark as brainlist

Step-by-step explanation:

INER-CIRCLE OF CIRCUMFERENCE =176m

2πR=176m

2*22/7*R=176m

44/7*R=127

R=176*7/44 =28 m

so, the inner part of the circle=28m

now,

radius of outer circle=28+7=35m

circumference = 2πR

=2*22/7*R

=2*22/7*35

=44*5

=220m