Question

a^8+a^4b^4+b^8 factoriseplz answer fast

Answer 1

Step-by-step explanation:

a^8+a^4b^4+b^8

=(a^4)^2+(b^4)^2+a^4b^4

=(a^4+b^4)^2-2a^4b^4+a^4b^4

=(a^4+b^4)^2-a^4b^4

=(a^4+b^4)^2-(a^2b^2)^2

=(a^4+b^4+a^2b^2)(a^4+b^4-a^2b^2)

=(a^4+a^2b^2+b^4)(a^4-a^2b^2+b^4)