Question

(a^8-b^8)by (a^2+b^2)​

Answer 1

Answer:

a^6-b^6

Step-by-step explanation:

you can divide it so by law of exponent

a^8-b^8÷a^2+b^2

=(a^8-2)-(b^8-2)

=a^6-b^6

Answer 2

Answer:

(a^4+b^4)(a^2-b^2)

Step-by-step explanation:

(a^8-b^8)= (a^4)^2-(b^4)^2  [∵ (a^m)^n=a^mn]

(a^4)^2-(b^4)^2 =[(a^4)-(b^4)][(a^4) + (b^4)]  {∵a^2-b^2 =(a+b)(a-b)}

[(a^4)-(b^4)][(a^4) + (b^4)]  = (a^2)^2-(b^2)^2(a^2+b^2)[(a^4) + (b^4)]    [∵ (a^m)^n=a^mn]

(a^2)^2-(b^2)^2(a^2+b^2) [(a^4) + (b^4)] = (a+b)(a-b)(a^2+b^2)(a^4+b^4)

Now (a^2+b^2) by (a^2+b^2) = (a^2-b^2)(a^4+b^4)