Question

A
8. From the adjoining figure, find
a) the area of AABC
6 cm
b) length of AC
c) the length of an
altitude from B to AC.​

Answer 1

Step-by-step explanation:

a)Base of ∆ABC = 8cm

Height or perpendicular of ∆ABC = 6cm

Area of the triangle = 1/2 X b X h

= 1/2 X 8 X 6

= 24cm²

The area of ∆ ABC is 24cm².

b) AC is the hypotenuse of ∆ ABC.

So, by applying pythagoras theorem,

h² = b² + p²

h² = 8² + 6²

h² = 64 + 36

h² = 100

h = √100

h = 10cm

The length of AC is 10cm.

c) To find the altitude BD,

Divide the twice of area of the triangle to the length of side on which altitude BD is i.e. AC.

So, 2 X 24 / 10

= 48/10

= 4.8cm

So, the length of BD is 4.8cm.

Hope it helped!

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