Physics, asked by vishagh, 1 year ago

A 8 kg block is connected to an empty 1.00 kg bucket by a cord running over a frictionless pulley. The coefficient of static friction between the table and the block is 0.5, Sand is gradually added to the bucket until the system just begins to move.Find the mass of sand added.

Answers

Answered by abhi178
11
for 8kg block
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body moves forward after m kg sand put in 1 kg block .
so, friction act on it backward ,

at equilibrium condition,
fr = T
uN = T ---(1)

for 1 kg block ,
at equilibrium condition,
when body start to move downward
T = ( m + 1) g
put eqn in here
uN = (m +1)g
uMg = ( m +1)g
uM = m +1

m = uM -1 = 0.5× 8 -1 = 4 -1 = 3 kg

abhi178: i hope this will correct
vishagh: Yeah.even i got the same answer,bu the answer key says igs 7kg. Tht may be wrong
vishagh: Thnx abhi
abhi178: yes 7kg is wrong , not possible , if static friction exist in table
vishagh: Yeah..thnx abhi
abhi178: :-)
abhi178: thanks bella
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