A 8 kg body moves towards the west with a momentum of 30 kg m s^-1. A 20 N force to the east acts on the body for a period of 5 s. Determine the magnitude and direction of
i. the impulse of the forces
ii. the change in the momentum of the body
iii. the final momentum of the body
iv. the final velocity of the body
Answers
Answer:
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Explanation:
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Given: mass of body = 8kg
momentum of body = 30kgms⁻¹
Force = 20N
Time for which force acts = 5second
To find : (a) impulse of the forces
(b) change of momentum of the body
(c) final momentum of the body
(d) final velocity of the body
Solution:
(a) Impulse of the force = Force × time for which force acts
= 20 × 5
= 100 Ns
Therefore, the impulse of the force is 100Ns and its direction is in the east.
(b) Change of momentum of the body is the impulse of the force.
Therefore, the change of momentum is 100Ns
(c) Change of momentum is 100Ns
initial momentum = 30kgms⁻¹
change in momentum = final momentum - initial momentum
100 = final momentum - 30
Therefore, the final momentum of the body is 130kgms⁻¹
(d) Final momentum of the body is 130kgms⁻¹
momentum = mass × velocity
130 = 8 × velocity
Therefore, the final velocity of the body is 16.25ms⁻¹