Question

A 8 meter ladder leaned against the wall.The base of the ladder is 6 meter.Find the height of the wall

Answer 1

the hypotenuse is 8 m

base is 6 m

∵ the angle formed between the base and wall is 90°

by pythagorus theorem we can find out the height

8²-6²=height²

64-36=height²

28=height²

√28=height

hope it helps

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Height\:of\:wall=5.29\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a 8 meter ladder leaned against the wall.The base of the ladder is 6 meter.

• We have to find the height of wall.

$\green{\underline \bold{Given :}} \\ : \implies \text{Length\:of\:ladder=8\:m} \\ \\ : \implies \text{Distance\:between\:wall\:and\:foot\:of\:ladder=6\:m}\\\\ \red{\underline \bold{To \: Find:}} \\ : \implies \text{Height\:of\:wall= ?}$

• Accroding to given question :

$\bold{ By \: pythagoras \: theorem} \\ : \implies {h}^{2} = {p}^{2} + {b}^{2} \\ \\ : \implies {AC}^{2} = {AB}^{2} + {BC}^{2} \\ \\ : \implies {8}^{2} = {AB}^{2} + 6^{2} \\ \\ : \implies 64 = {AB}^{2} +36 \\ \\ : \implies 64- 36 = {AB}^{2} \\ \\ : \implies {AB}^{2} = 28 \\ \\ : \implies AB= \sqrt{28} \\ \\ \green{: \implies \text{AB= 5.29 \: m}}$