A 8 ohm resistance wire is stretched to double its length the new resistance of a wire will be
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When a wire is stretched, its volume will remain the same.
Since Volume = Area x length, given that length has increased two times, the area will be halved.
So, new length = 2L. New Area = A/2
Resistance is proportional to Length/Area.
New resistance is proportional to 2L/(A/2)
New resistance = 4R
Thus resistance increases by 4
I have told u the process.Thecrest u do yourself.
Since Volume = Area x length, given that length has increased two times, the area will be halved.
So, new length = 2L. New Area = A/2
Resistance is proportional to Length/Area.
New resistance is proportional to 2L/(A/2)
New resistance = 4R
Thus resistance increases by 4
I have told u the process.Thecrest u do yourself.
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