A 80 mH inductor and a 60 uF capacitor are
connected to a 230 V, 50 Hz supply. If the rms
current in the circuit is Irms = 8.24 A, calculate
the rms value of potential drop across each
element.
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Answer:
across inductor potential drop = 32.96
across capacitor potential drop = 2750
Explanation:
- XL = wL=4, VL = i×XL= 33
- Xc = 1/wc=1000/3, Vc= i× xc =2750
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