Question

A 80 ohm galvanometer shows a deflection of 1 division
per mA. It has 50 divisions on its scale. If a shunt of
2.5 ohm be attached to the galvanometer, what maximum
current will this galvanometer measure? ​

Answer 1

Answer:

the answer is:

210 A

Explanation:

I

g

=

5

50

=10mA;

R

g

= 40 Ω, R

s

= 2Ω

Maximum current,

I=

R

g

R

g

+R

s

X I

g

=

2

(40+2)×10

= 210mA