A 8000 kg engine pulls a train of 5 wagon each of 2000kg along a horizontal track if the engine exert a force of 40000 newton and the track offers a friction force of 5000 newton ,then calculate the net acceleration of the train ; the net acceleration force and the force of wagon 1 on wagon 2
Answers
Answer : Given, force of engine = 40000 N
Force of friction = 5000 N
Mass of engine = 8000 kg
Total weight of wagons = 5 x 2000 kg = 10000 kg
(a) The net accelerating force
= Force exerted by engine – Force of fricition
= 40000 N – 5000 N = 35000 N
(b) The acceleration of the train
We know that, F = mass x acceleration
Or, 35000 N = (mass of engine + mass of 5 wagons) X a
Or, 35000N=(8000kg+10000kg)×a35000N=(8000kg+10000kg)×a
Or, 35000N=18000kg×a35000N=18000kg×a
⇒a=35000N18000 kg=1.944ms−2⇒a=35000N18000 kg=1.944ms-2
(c) The force of wagon 1 on wagon 2 = mass of four wagons x acceleration
⇒F=4×2000 kg×1.944ms−2⇒F=4×2000 kg×1.944ms-2
⇒F=8000 kg×1.944ms−2⇒F=8000 kg×1.944ms-2
⇒F=1552N⇒F=1552N
Thus, (a) The net accelerating force = 35000N
(b) The acceleration of train = 1.944 ms–2
(c) The force of wagon 1 on 2 = 1552 N
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