A 8000 kg engine pulls A train of 5 wagons, each of 2000 kg, Along a horizontal track. If the engine exert a force of 40, 000N and the track offers a friction force of 5,000 N, then calculate: (a) the net accelerating force (b) the acceleration of train (C) the force of wagan 1 on wagon 2 ★Plse answer fast
Answers
Answer:
mass of engine = 8000 kg
mass of 1 wagan = 2000 kg
mass of 5 wagons =5×2000 =10000 kg5×2000=10000kg
force exerted by the engine =40000 N
frictional force = 5000 N
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solution
(a) net accelerating force = force by engine -
friction force
= 40000 N - 5000N
= 35000N
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(b) acceleration of the train, a= \frac{net \: force}{mass \: of \: the \: train}
massofthetrain
netforce
\begin{lgathered}\implies \: a = \frac{35000}{8000 + 10000} = \frac{35000}{18000} \\ \\ a = 1.94 \: {ms}^{ - 2}\end{lgathered}
⟹a=
8000+10000
35000
=
18000
35000
a=1.94ms
−2
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(c) when wagon 1 applies force on wagon 2, then actually it has to apply force on the mass of 4 wagons.
since, the wagons are moving with the acceleration of 1.94 \: {ms}^{ - 2}1.94ms
−2
, the force acting on the four wagons (combined) will be the force exerted by wagan 1.
==>net mass of 4 wagons = 4×2000
= 8000kg
===>forcees by wagan 1 on wagan 2 = mass of 4 wagons × acceleration of the wagons
= 8000× 1.94
\implies \: F12 =15520⟹F12=15520
Explanation:
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