A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate:
(a) the net accelerating force;
(b) the acceleration of the train; and
(c) the force of wagon 1 on wagon 2.
Answers
Hey mate,..
a)Mass of the engine = 8000 kg
Mass of each wagon = 2000 kg,
Np. of wagons = 5
mass of total wagon=2000*5
=10000
b)Total mass of train = 8000+2000*5= 18000 kg
Force, F = 40000 N
Track resistance , R = 5000 N
Total accelerating force = F −R
=40000−5000
=35000 N
c)Let acceleration = y m/s²
Acceleration = Accelerating force / mass
y=35000/18000
= 35/18
=1.94 m/s²
Frictional resistance of 4 wagons = 5000*(2000*4)/18000 =2222 .22 N
Accelerating force on 4 wagons =2000*4*1.944 =15552 N
Hence total force exertred by wagon on wagon 2= Accelerating force +Frictional resistance
=2222 .22 +15552=17774.22 N
Hope it will help you
Answer:-
Given:-
Mass of the engine = 8000 kg
Mass of each wagon = 2000 kg,
Np. of wagons = 5
(a) The net accelerating force = Force exerted by the engine – friction force
⇒40000 N – 5000 N = 35000 N
= 35000 N
(b) The acceleration of the train (a) = ?
F = 35000 N
Mass of 5 wagons pulled by engine
⇒ 5 × 2000
⇒ 10000 kg
⇒ F = ma
⇒ 35000 = 10000 × a
⇒ a = 3.5 m/s²
= 3.5 m/s²
c) Total mass pulled by wagon 1 = 2000 × no of remaining wagons except wagon 1
⇒ 2000 × 4
⇒ 8000 kg
⇒ force exerted by wagon 1 on wagon 2 = Mass pulled by wagon 1 × acceleration
⇒ 8000 × 3.5
= 28000 N
Explanation:-
From Newton's second law we have a connection between Forces F and the acceleration a (via mass).
F = ma
Where;
F = Newtons (N) Vector
m = mass (kg) Scalar