Question

a 8000 kg engine pulls a train of wagon , each of 2000 kg , along a horizontal track . if the engine exerts a force of 40000N and the tracks offers a friction of 4000N , then calculate net force and acceleration​

Answer 1

Answer:

Given parameters

Mass of the engine = 8000 kg

Number of wagons = 5

Mass of the wagons = 2000 kg

Force exerted by the engine (F ) = 40000 N

Frictional force offered by the track (Ff) = 5000 N

(a) Net accelerating force (Fa) = F – Ff

Fa = 40000 N – 5000 N

Fa = 35000 N

(b) Let us consider the acceleration of the train be a m/s2

Acceleration is the ratio of net acceleration force by mass, i.e

a = Fa/m

Where m is the mass of the train, it can be calculated as follows

Total mass of the train (m) = Mass of the engine + (Mass of the wagons + Number of wagons)

m = 8000 + (5 × 2000)

m = 18000 kg

Acceleration of the train (a) = 35000/18000

a = 1.944m/s2

(c) Force of wagon 1 on wagon 2 = 4 × mass of wagon × a

Force of wagon 1 on wagon 2 = 4 × 2000 × 1.944

Force of wagon 1 on wagon 2 = 15552 N

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Answer 2

Answer:

40

Explanation:

8000/2000

=4

40000/4000

=10

then 4×10 =40