Question

A 8000kg engine pulls a train of 5 wagons , each of 2000kg ,along a horizontal track. If the engine exerts a force of 40000N and the track offers a friction force of 5000N , then calculate:
1) The net accelerating force
2) The acceleration of the train

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Answer 1

Answer:

$<marquee behaviour="slide" direction="up" style ="background: violet">$(a) Force exerted by the engine, F = 40000 N

Frictional force offered by the track, Ff = 5000 N

Net accelerating force, Fa = F Ff = 40000 5000 = 35000 N

Hence, the net accelerating force is 35000 N.

(b) Acceleration of the train = a

The engine exerts a force of 40000 N on all the five wagons.

Net accelerating force on the wagons, Fa = 35000 N

Mass of the wagons, m = Mass of a wagon x Number of wagons

Mass of a wagon = 2000 kg

Number of wagons = 5

m = 2000 — 5 = 10000 kg

Total mass, M = m = 10000 kg

From Newton’s second law of motion:

Fa= Ma

a=Fam = 35000 10000 = 3.5 ms^(-2)

Hence, the acceleration of the wagons and the train is 3.5 m/s2.

Answer 2

$\huge\star\underline\mathfrak\red{Answer:-}$

1) F = 40000N

F1 = 5000N

Fa = F-F1

= 40000-5000

= 35000N

Hence, the net accelerating force is 35000N.

2) Acceleration of the train = a

The engine exerts a force of 40000N on all the five wagons.

Mass of the wagon = 2000kg

No. of wagons = 5

therefore, m = 2000×5

= 10000kg

Total mass (including the mass of engine),M = m+8000

= 18000kg

Fa = Ma

= a = Fa/M

= 35000/18000

= 1.944m/s^2