Question

A 8000kg engine pulls a train of 5 wagons each of 2000kg along a horizontal track. If the engine exerts a
force of 40000N and the track offers a frictional force of 5000N, then calculate
a) The net acceleration force
b) The acceleration of the train
c) The force of wagon 1 on wagon 2

Answer 1

Answer:

Given parameter

Mass of engine (M) = 8000 kg

No. of wagons = 5

Mass of the wagons(m) = 2000 kg

Force exerted by the engine (F) = 40000N

Frictional force offered by the Track(Ff)=5000N

a) The net acceleration force .

(Fa) = F – Ff

Fa = 40000 N – 5000 N

Fa = 35000 N

B) The acceleration of the train

Let us consider the acceleration of the train be a m/s2

Acceleration is the ratio of net acceleration force by mass, i.e

a = Fa/m

Where m is the mass of the train, it can be calculated as follows

Total mass of the train (m) = Mass of the engine + (Mass of the wagons × Number of wagons)

m = 8000 + (5 × 2000)

m = 18000 kg

Acceleration of the train (a) = 35000/18000

a = 1.944m/s2

c) The force of wagon 1 on wagon 2

The external force is only applied to waggon 1 directly. On the last four waggons, the net force is equal to the force added to waggon 2 by waggon 1.

Let us consider the acceleration of the wagons is aw

35000 = 5m × aw

aw = 35000/5m

aw = 35000/(5 × 2000)

aw = 3.5 m/s2

Then the mass of last four wagons can be considered as mw

mw = 2000 × 4

mw = 8000 kg

Now let us calculate the net force on the last four wagons

F’ = mw× aw

F’ = 8000 × 3.5

F’ = 28000 N

∴ The force of wagon-1 on the wagon-2 is 28000N.

Brainliest .. !! ⚡