A 8000kg engine pulls a train of 5wagons each of 2000kg along a horizontal track in the engine exerts a force of 40000N and then track offers a friction force of 5000N then calculate.
(a) they net accelerating force
(b) the acceleration of The train
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Answers
Explanation:
force exerted by the engine is F1 = 40000N
frictional force exerted by track ,F2= - 50000 N
negative sign shows that friction is opposite to direction of motion
i)net accelerating force = F1+F2
= 40000+(-50000)
= -10000N
ii) mass of each wagon = 2000 kg
no. of wagons = 5
mass of train ( without engine) (m)= 2000×5
= 10000 kg
net accelerating force = -10000N
from,
F=ma
a=F/m
a= -10000/10000
a= -1 m/s^2
therefore acceleration of train = -1m/s^2
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Answer:
force exerted by the engine is F1 = 40000N
frictional force exerted by track ,F2= - 50000 N
negative sign shows that friction is opposite to direction of motion
i)net accelerating force = F1+F2
= 40000+(-50000)
= -10000N
ii) mass of each wagon = 2000 kg
no. of wagons = 5
mass of train ( without engine) (m)= 2000×5
= 10000 kg
net accelerating force = -10000N
from,
F=ma
a=F/m
a= -10000/10000
a= -1 m/s^2
therefore acceleration of train = -1m/s^2