Question

A 815 torr y 48,4 °C, 7.81 g de un gas ocupan un volumen de 5940 mL ¿cuál será la masa molar del gas? n = masa de la sustancia / masa molar.

Answer 1

Answer:-

Given:

Pressure of the gas (P) = 815 torr

Temperature (T) = 48.4 ° + 273.15 K = 325.55° K

Volume (V) = 5940 ml = 5.940 L

Mass of the gas (m) = 7.81 g

R (Gas Constant) = 62.3 L*torr/K*mol.

By using Ideal Gas Equation,

→ PV = nRT

→ PV = m/M * RT (M = molar mass)

→ (815)(5.940) = 7.81 / M * 62.3 * (325.55)

After cross multiplication we get,

→ M(815)(5.940) = 7.81(62.3)(325.55)

→ M = (7.81)(62.3)(325.55)/(815)(5.940)

→ M = (158400.58465)/4841.1

→ M = 32.7 g/mol.