Question

A 8kg of water at 23 degree Celsius is poured to 2kg of hot water and the final temperature is 37 degree Celsius. What is the initial temperature of hot water?

Answer 1

Explanation:

Specific heat capacity of water=4200 J/kgK

By the principle of mixtures,

m x c (T1-T) = m x c x(T-T2)

2 x 4200(80-T) = 8 x 4200(T-25)

(4200 on both sides get cancelled)

160-2T = 8T-200

360 = 10T

T= 36 degree Celcius