Question

A(-9,0),B(-1,0) are two points.If P is a point such that PA:PB=3:1.Then the locus of P is x²+y²=k
The value of K is

Answer 1

Answer:

2

+y

2

=9

Step-by-step explanation:

Let P(x,y) be a point lying on the curve.

Then 3PB=PA

3

(x+1)

2

+y

2

=

(x+9)

2

+y

2

Squaring both sides give us:

9(x+1)

2

+9y

2

=(x+9)

2

+y

2

⇒(3x+3)

2

−(x+9)

2

+8y

2

=0

⇒(4x+12)(2x−6)+8y

2

=0

⇒8(x+3)(x−3)+8y

2

=0

⇒(x+3)(x−3)+y

2

=0

⇒x

2

−9+y

2

=0

⇒x

2

+y

2

=9

Answer 2

Step-by-step explanation:

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