Question

A(-9,0), B(-1,0) are two points. If P is a point such that PA : PB = 3:1, then the locus of P is
a) x^2-y^2+ 9 = 0
b) x^2 + y^2 = -9
c) x² + y^2 = 9
d) x² - y^2 = 0 ​

Answer 1

Step-by-step explanation:

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