a=9+4root5and b=1/a,find value of a^2+b^2
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a=9+4√5
b=1/a
= 1/(9+4√5)
= 9-4√5. ( on rationalizing)
now a²+b²
(9+4√5)²+(9-4√5)²
= 81+80+2(9*4√5)+81+80-2(9*4√5)
= 322
b=1/a
= 1/(9+4√5)
= 9-4√5. ( on rationalizing)
now a²+b²
(9+4√5)²+(9-4√5)²
= 81+80+2(9*4√5)+81+80-2(9*4√5)
= 322
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the answer is 2 a square plus two a b plus b square is answer
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