A 9 f capacitor of a heart defibrillator is charged to 8000 v. (a) how much energy is stored? (b) how much charge is stored?
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Here,
C=9f
V=8000
Energy stored is given by:
E=1/2 X CV²
=1/2 X 9 X 8000 X 8000
= 2.88 X 10^5 kilojoule
Charge stored is :
Q=CV
=9 X 8000
=72000 coulomb
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C=9f
V=8000
Energy stored is given by:
E=1/2 X CV²
=1/2 X 9 X 8000 X 8000
= 2.88 X 10^5 kilojoule
Charge stored is :
Q=CV
=9 X 8000
=72000 coulomb
Mark as brainleist
Hope it helps you
^_^
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