Question

a 9 ohm resistance is double on it calculate the new resistance of the wire​

Answer 1

Answer:

Explanation:

Resistance=ρL/A Here, Resistance=6ohm Therefore,6=ρL/A In second case, Resistance,R'=ρL'/A' As the wire is doubled so L'=L/2, A'=2A So new resistance,R'=ρL/4A=(1/4)ρL/A But ρL/A=9 So, R'=9/4=2.25Ω

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