a=90 , d=20, find the sum of 20th term.
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Answered by
1
Howdy!!
your answer is --
Given, a = 90 & d = 20
therefore
S20 = 20/2 [2a + 19d]
= 10[ 2×90+19×20]
= 10[560] = 5600
hope it help you_____
your answer is --
Given, a = 90 & d = 20
therefore
S20 = 20/2 [2a + 19d]
= 10[ 2×90+19×20]
= 10[560] = 5600
hope it help you_____
Answered by
2
First term = a = 90
Last term =20th term
Last term = a+19d =90+19(20)
Last term = 90+380
Last term = 470
Now,
Sum of n term = n/2 [last term+ first term]
Here,
Sum of 20 term = 20/2 [470+90]
Sum of 20 terms =10×560
Sum of 20 term = 5600
I hope this will help you
-by ABHAY
Last term =20th term
Last term = a+19d =90+19(20)
Last term = 90+380
Last term = 470
Now,
Sum of n term = n/2 [last term+ first term]
Here,
Sum of 20 term = 20/2 [470+90]
Sum of 20 terms =10×560
Sum of 20 term = 5600
I hope this will help you
-by ABHAY
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