A 900 gram of ball moving at
29ms-1 shows down uniformly
until it stops. Calculate the
average net force applied on it
to come to rest with in a
distance of 45 m.
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Answer:
mass of the ball m =500g =0.5kg
velocity of the ball V = 15ms
−1
distance travelled =s =15m
from v
2
−u
2
=2as⟹v
2
=u
2
+2as
0=15
2
+2a(15)
-225=30a ⟹ a= -7.5ms
−2
net force applie F=M×a
F=0.5 ×(−7.5)
= -3.75N
this force 3.75 N has to be applied in the opposite direction
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