Question

A 9000N automobile is pushed along a level road
by four students who apply a total forward force
of 500N. Neglecting friction, the acceleration of the
automobile is:
(1) 0.055m/s2 090.54m/s2
(3) 1.8m/s2
(4) 9.8m/s2​

Answer 1

Answer:

2)0.54m/s²

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Answer 2

Given:

Weight of automobile $\[ = 9000N\]$

Force applied on automobile $\[ = 500N\]$

To Find: Acceleration of the automobile

Solution:

According to Newton's second law of motion, the force is given as

$\[Force = mass \times acceleration\]$

Therefore, acceleration can be given as

$\[Acceleration = \frac{{Force}}{{Mass}}\]$

Mass of the automobile can be obtained by dividing the given weight by $\[9.8m/{s^2}\]$

Therefore, the mass of the automobile is

$\[Mass = \frac{{9000N}}{{9.8m/{s^2}}}\]$

$\[Mass = 918.36kg\]$

Thus, acceleration of the automobile

$\[Acceleration = \frac{{500N}}{{918.36kg}}\]$

$\[Acceleration = 0.54m/{s^2}\]$

Hence, the acceleration of the automobile is $\[0.54m/{s^2}\]$.