Question

A 90kg canon fires 100kg shell with muzzle velocity of 75m/s. Calculate the recoil velocity of the canon relative to the ground

Answer 1

Answer:

(m1)=90kg

m2=100kg

v2=75m/s

v1=?

from principle of conservation of

linear momentum,

initial momentum=final momentum

0=m1.v1+m2.v2

0=90.v1+100.75

90.v1 =-7500

v1=-7500/90

:v1=-83.33m/s

-'ve sign indicate velocity of canon

Is in opposite directions..

Answer 2

Answer:

-83.33m/s

Explanation:

m1=90kg

m2=100kg

v2=75m/s

v1=?

principle of conservation linear momentum-

initial momentum = final momentum

0=m1xv1+m2xv2

0=90xv1+100x75

90v1= -7500

v1 = -7500

90

v1=-83.33m/s

here negative sign shows the velocity of canon is in opposite direction.

I think you got it.