a) 937 (e) 572 Directions (31-35): The following questions are based on the five three digit numbers given below: 374 659 821 945 247 31. If 1 is subtracted from the last digit of each numbers how many numbers thus formed is divisible by two? (a) None (b) one (C) two (d) three (e) four 32 Tf in each
Answers
Answer:
Sahil Kumar bhadu Bishnoi
Given :- five three digit numbers : 374, 659, 821, 945, 247 .
To Find :- If 1 is subtracted from the last digit of each numbers how many numbers thus formed is divisible by two? (a) None (b) one (C) two (d) three (e) four .
Concept used :- Divisibility rule of 2 :-
- If unit of a number is 0, 2, 4, 6 or 8 the given number is divisible by 2 .
Solution :-
Subtracting 1 from unit of given numbers we get,
a) 374
→ 374 - 1 = 373 = Unit digit 3 .
since unit digit of number is not 0, 2, 4, 6 or 8 . The number so formed is not divisible by two .
b) 659
→ 659 - 1 = 658 = Unit digit 8 .
since unit digit of number is 8 . The number so formed is divisible by two .
c) 821
→ 821 - 1 = 820 = Unit digit 0 .
since unit digit of number is 0 . The number so formed is divisible by two .
d) 945
→ 945 - 1 = 944 = Unit digit 4 .
since unit digit of number is 4 . The number so formed is divisible by two .
e) 247
→ 247 - 1 = 246 = Unit digit 6 .
since unit digit of number is 6 . The number so formed is divisible by two .
Therefore, we can conclude that total (e) four number so formed are divisible by two .
Shortcut :- Check the given number as even or odd number .
- Odd number - 1 = Divisible by two .
- Even number - 1 = Not divisible by two .
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