A 950 kg sack of cement is li# ed to the top of a building 50 m high by an electric motor.
a Calculate the increase in the gravitational potential energy of the sack of cement. b The output power of the motor is 4.0 kW. Calculate how long it took to raise the sack to the top
of the building. c The electrical power transferred by the motor is 6.9 kW. In raising the sack to the top of the building,
how much energy is wasted in the motor as heat?
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Answer:
a
Explanation:
a. potential energy = m x g xh = 950 x 9.8 x 50 j
b. power = work / time = potential energy / time
time = potential energy /power
= ( 950 x 9.8 x 50) / 4 x 1000 s
c. heat = power x time
= ( 6.9 - 4) 1000 x ( 950 x 9.8 x 50) / 4000J
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