Question

A 96 cm long wire is given the shape of a rectangle such that its length is 12 cm more than
the breadth. Find the length and breadth of the rectangle.
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Answer 1

$\sf{\huge{\underline{\purple{Given :-}}}}$

• A 96 cm long wire is given the shape of a rectangle such that its length is 12 cm more than
• the breadth.

$\sf{\huge{\underline{\pink{To\:Find :-}}}}$

• The length and breadth of the rectangle.

$\sf{\huge{\underline{\blue{Solution :-}}}}$

The perimeter of the wire is 96cm.

Let, the breadth be x,

Where as length = x + 12

We, know

Perimeter of rectangle wire = 2(length + breadth)

➝ 96 = 2( l + b )

➝ 2(x + x + 12) = 96

➝ x + x + 12 = 96/2

➝ 2x + 12 = 48

➝ 2x = 48 - 12

➝ 2x = 36

➝ x = 36/2

➝ x = 18

• Breadth of rectangle = x = 18cm

• Length of rectangle = x + 12 = 30cm

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Answer 2

$\huge\star \big \bf \ Gɪᴠᴇɴ$

• A 96 cm long wire is given the shape of a rectangle such that its length is 12 cm more than

the breadth.

$\huge \star \sf \: To \: Find:$

The length and breadth of the rectangle.

Sᴏʟᴜᴛɪᴏɴ:-

The perimeter of the wire is 96cm.

Let, the breadth be x,

Where as length = x + 12

We, know

Perimeter of rectangle wire = 2(length + breadth)

$\begin{gathered} \sf ➝ 96 = 2 ( l + b ) \: \: \: \: \: \: \: \: \: \: \ \\ \sf➝ 2(x + x + 12) = 96 \\ \sf➝ x + x + 12 = 96/2 \\ \sf ➝ 2x + 12 = 48 \: \: \: \: \: \: \: \: \: \: \: \\ \sf ➝ 2x = 48 - 12 \: \: \: \: \: \: \: \: \: \: \\ \sf➝ 2x = 36 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf ➝ x = 36/2\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf➝ x = 18 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \end{gathered}$

Breadth of rectangle = x = 18cm

Length of rectangle = x + 12 = 30cm

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