Question

A 9V battery is connected to a resistor 0 points having a resistance of 10 Q2. What is the current and power across the resistor?

Answer 1

Answer:

Step 1  Finding the equivalence resistance

For resistors in series,

R

eq

​

=R

1

​

+R

2

​

+R

3

​

+R

4

​

+R

5

​

      =0.2+0.3+0.4+0.5+12

      =13.4 Ω  

Step 2: Finding the current.

Using the ohm's Law:

V=IR

eq

​

9=13.4I

I=0.67 A

When resistors are connected in series, the current is  same in all the resistors. Hence, current in 12 Ω resistor =0.67 A.