Question

a(a+1/a)-b(b-1/b)-c(c+1/c)

Answer 1

A+1\B=1——————(1)

B+1\C=1———————(2)

B=1–1\C

Substituting in (1),we get

A+C/(C-1)=1

On cross multiplication, AC-A+C=C-1

Thus AC-A=-1 or A=1\(C+1)——————-(3)

Now , C+1\A=C+C+1=2C+1=2C+2–1=2(C+1)-1=(2\A)-1 from (3)

=(2\(1–1\B))-1

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