(a+(√a^2-2ax))/((a-(√a^2-2ax)) = b Solve....
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a Is −2axa
+1=b⇒ a 2 −2axa
=b−1; Squaring1
a 2 −2axa 2
=(b−1) 2 ⇒ a 2
a 2−2ax
=(b−1) 2 ⇒1− a2x
=(b−1) 2 ⇒ a2x
=1−(b−1) ⇒x= 2a
[−b 2 +2b]
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