Question

a+a=2 a+b=3 a+b+c=6 a+b+c×4=?

Answer 1

$a + a = 2 \\ \\ 2a = 2 \\ \\ a = \frac{2}{2} = 1 \\ \\ a + b = 3 \\ \\ b \: = 3 - a \\ \\ b = 3 - 1 \\ \\ b = 2 \\ \\ a + b + c = 6 \\ \\ c = 6 - (a + b) \\ \\ c = 6 - 3 = 3 \\ \\ a = 1 \\ b = 2 \\ c = 3 \\ \\ a + b + c \times 4 = 1 + 2 + 3 \times 4 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3 + 12 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 15$

Answer 2

Answer:

The required value is $15$.

Step-by-step explanation:

It is given that $a+a=2$

$a+b=3$

$a+b+c=6$

$a+b+c*4=?$

We need to determine the value of $a+b+c*4=?$

From first equation, $a+a=2$

$a=1$

Using it in second equation

$1+b=3$

$b=3-1=2$

$b=1$

Using both in third equation,

$1+2+c=6$

$c=6-3=3$

Using it in one which we have to calculate $a+b+c*4=1+2+3*4=15$

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