Question

a+a=2, a+b=3, a+b+c=6 then a+b+c*4=?

Answer 1

a+a=2

2a=2

a=2/2=1

a=1

a+B=3

1+B=3

B=3-1

B=2

a+B+c=6

1+2+c=6

3+c=6

c=6-3

c=3

a+B+c*4

1+2+3*4

1+2+12 { bodmas rule}

15

plz mark as brainliest

plz mark

Answer 2

Answer:

The answer is 15

Step-by-step explanation:

Given,

a + a = 2

2 a = 2

Dividing both the sides by 2;

2a / 2 = 2 / 2 = 1

Therefore,

a = 1

Now, it is also given,

a + b = 3

Substituting the value of a = 1

1 + b = 3

b = 3 - 1

b = 2

Therefore , b = 2

Also, It is given :

a + b + c = 6

Substituting value of a and b

1 + 2 + c = 6

3 + c = 6

c = 6 - 3

c = 3

We need to find value of  :

a + b + c * 4

Substituting values of a , b and c

= 1 + 2 + 3 * 4

= 1 + 2 + 12

= 3 + 12  

= 15

Hence,

The answer is 15