Question

a(a-2b-c)+2bc .factorise​

Answer 1

Step-by-step explanation:

a(a-2b-c)+2bc

= a²-2ab-ac+2bc

= a²-ac-2ab+2bc

= a(a-c)-2b(a-c)

= (a-2b)(a-c)

so, (a-2b) and (a-c) are two factors of a(a-2b-c)+2bc

Answer 2

Answer:

$a ^{2} - 2ab - ac + 2bc$

$a(a - 2b) - c(a - 2b)$

Hope it helps

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