a (a_ 3b)² + b (3a-b)^2
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Answer:
a(a-3b) ² + b(3a-b) ²
→a(a²-6ab+9b²) + b(9a²-6ab+b²)
=a³-6a²b+9ab²+9a²b-6ab²+b³
=a³+3a²b+3ab²+b³
=(a+b)³
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