a) A 6 ohm resistance wire is doubled on itself. Calculate the new resistance of the wire
(b) Three 2 ohm resistors A, B and C are connected in such a way that the total resistance of the combination is 3 ohm. Show the arrangement of the three resistors and justify your answer.
Answers
Answered by
5
Answer:
a) when doubled on itself, it will act as resistors in parallel connection. use the formula 1/R eq= 1/R1 +1/R2.....
Answered by
9
Answer:
a) R=6Ohm
as R=PL/A=6ohm
new resistance when length becomes half and areaa becomes double
R'=pl/2/2A=pl/4A
as pl/A=6
therefore R'=6/4=1.
Similar questions