Question

a+a+a=21 , b+b+a =19 , c+b+a =15 , then what is a+b*c = ? what is the answer

Answer 1

Answer:

19

Step-by-step explanation:

from 1:

3a=21

a=7

from 2:

2b+7=12

2b=12

b=6

from 3:

c+6+7=15

c+13=15

c=2

Therefore a+b*c=7+6*2

=7+12

=19

Answer 2

Answer: 15

Step-by-step explanation:

3 pigs = 21 so 1 pig is 21 ÷ 3 = 7

So 1 pig (a) = 7

2 buses + 1 pig (7) = 19

so we minus the pig (7) from the total = 19-7= 12

Therefore 2 buses = 12

1 bus = 12÷2=6

1 bus (b) = 6

1 hat + 1 bus (6) +1 pig (7) = 15

now we minus the pig from the total 15-7 = 8

As you can see, 8 = 1 bus + 1 hat

So if we minus the bus(8) from the total we would get 2           (8-6=2)

That means a hat is 2

so the question states a pig + a hat × a bus

                                          7   +     2   ×    6

7+2=9

9×6=15