A+A+A = 24 A+B =20 2B + C =30 A+B+C=???
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Answer: The value of A+B+C= 26
Step-by-step explanation:
Given are the 3 equations,
i)A+A+A = 24
ii)A+B =20
iii)2B + C =30
To find: A+B+C
From (i) A+A+A = 24
i.e, 3A = 24
Dividing 3 from both sides, we get,
A = 8
Now, from (ii) A+B = 20
Putting the value of A in the above equation, we get,
8 + B = 20
Subtracting 8 on both sides, we get,
8 + B - 8 = 20 - 8
∴ B = 12
Now, from (iii) 2B + C =30
Putting the value of B in the above equation, we get,
2(12) + C =30
∴ 24 + C = 30
Subtracting 24 on both sides, we get,
24 + C -24 = 30 - 24
∴ C = 6
Now, we need to find the value of
A+B+C,
Putting the values of A,B,and C in the above equation, we get,
8 + 12 + 6 = 26
Hence the required sum is 26.
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