Math, asked by shrabonibba, 2 months ago

(a+a+a)=(b+b+b+b) and a+b=7 then what is the value of a^2-b^2?​

Answers

Answered by sakshithakur6704
0

Answer:

Step-by-step explanation:

(a+a+a) =( b+b+b+b)

3a=4b

a=4b/3

by 2nd eq , we get..

a+b=7

a=b-7  ....(2)

4b/3=b-7

4b=3b-21

b= -21

a = 4 (-21) / 3

a = -28

a^2 - b^2 = (-28)^2 - (-21)^2

= 343

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